1 Values of log Ks were taken from an enlarged graph and fitted to an equation by the compiler as follows: log10Ks = 6.5583 - 866.67 (T/K)-1
Ks = a form of Henry's constant, mmHg pressure (mo1/1)-1
2 A more common Henry's constant (H) and mole fraction ethene solubility for a partial pressure of 101.3 kPa were calculated by the compiler.